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kub999
@kub999
July 2022
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Известно , что f(x) =3/x^2-64,g(x)=7/64-x^2 . Найдите значения переменной , при которых f(x)>g(x)
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kirichekov
Verified answer
3/(x²-64) >7/(64-x²)
3/(x²-54)-7/(64-x²>0)
3/(x²-64)+7/(x²-64)>0
(3+7)/(x²-64)>0, 7>0⇒x²-64>0
метод интервалов:
1. x²-64=0. x₁=-8, x₂=8
+ - +
2. ----------|-----------|------------>x
-8 8
x∈(-∞;-8)U(8;∞)
9 votes
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Answers & Comments
Verified answer
3/(x²-64) >7/(64-x²)3/(x²-54)-7/(64-x²>0)
3/(x²-64)+7/(x²-64)>0
(3+7)/(x²-64)>0, 7>0⇒x²-64>0
метод интервалов:
1. x²-64=0. x₁=-8, x₂=8
+ - +
2. ----------|-----------|------------>x
-8 8
x∈(-∞;-8)U(8;∞)