[tex]\displaystyle\bf\\1)\\\\3\cdot 81^{\frac{1}{4} } =3\cdot\Big(2^{4} \Big)^{\frac{1}{4} } =3\cdot 2^{4\cdot\frac{1}{4} } =3\cdot 2=6\\\\\\2)\\\\32^{-\frac{1}{5} } =\Big(2^{5} \Big)^{-\frac{1}{5} } =2^{5\cdot(-\frac{1}{5} )} =2^{-1} =\frac{1}{2}=0,5\\\\\\3)\\\\16^{1,25} =\Big(2^{4} \Big)^{\frac{5}{4} } =2^{4\cdot\frac{5}{4} }=2^{5} =32[/tex]
[tex]\displaystyle\bf\\4)\\\\\Big(6\frac{1}{4} \Big)^{-0,5} =\Big(\frac{25}{4} \Big)^{-0,5} =\Bigg[\Big(\frac{5}{2} \Big)^{2} \Bigg]^{-0,5} =\Big(\frac{5}{2} \Big)^{-1} =\frac{2}{5} =0,4[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
[tex]\displaystyle\bf\\1)\\\\3\cdot 81^{\frac{1}{4} } =3\cdot\Big(2^{4} \Big)^{\frac{1}{4} } =3\cdot 2^{4\cdot\frac{1}{4} } =3\cdot 2=6\\\\\\2)\\\\32^{-\frac{1}{5} } =\Big(2^{5} \Big)^{-\frac{1}{5} } =2^{5\cdot(-\frac{1}{5} )} =2^{-1} =\frac{1}{2}=0,5\\\\\\3)\\\\16^{1,25} =\Big(2^{4} \Big)^{\frac{5}{4} } =2^{4\cdot\frac{5}{4} }=2^{5} =32[/tex]
[tex]\displaystyle\bf\\4)\\\\\Big(6\frac{1}{4} \Big)^{-0,5} =\Big(\frac{25}{4} \Big)^{-0,5} =\Bigg[\Big(\frac{5}{2} \Big)^{2} \Bigg]^{-0,5} =\Big(\frac{5}{2} \Big)^{-1} =\frac{2}{5} =0,4[/tex]