Завдання 7.
1)
[tex]5x - 3y = 18 \\ - 3y = 18 - 5x \\ y = \frac{18 - 5x}{ - 3} \\ y = \frac{5x - 18}{3} [/tex]
2)
[tex]4a = 1 + 6ab \\ 4a - 6ab = 1 \\ a(4 - 6b) = 1 \\ a = \frac{1}{4 - 6b} [/tex]
Завдання 8.
(3x+y)²=(x+3y)²+8(x-y)(x+y)
(3x+y)²=(x+3y)²+8(x²-у²)
(3x+y)²=x²+2*х*3y+(3у)²+8x²-8у²
(3x+y)²=x²+6хy+9у²+8x²-8у²
(3x+y)²=9x²+6хy+у²
(3x+y)²=(3x)²+2*3х*y+у²
(3x+y)²=(3x+у)²
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Answers & Comments
Завдання 7.
1)
[tex]5x - 3y = 18 \\ - 3y = 18 - 5x \\ y = \frac{18 - 5x}{ - 3} \\ y = \frac{5x - 18}{3} [/tex]
2)
[tex]4a = 1 + 6ab \\ 4a - 6ab = 1 \\ a(4 - 6b) = 1 \\ a = \frac{1}{4 - 6b} [/tex]
Завдання 8.
(3x+y)²=(x+3y)²+8(x-y)(x+y)
(3x+y)²=(x+3y)²+8(x²-у²)
(3x+y)²=x²+2*х*3y+(3у)²+8x²-8у²
(3x+y)²=x²+6хy+9у²+8x²-8у²
(3x+y)²=9x²+6хy+у²
(3x+y)²=(3x)²+2*3х*y+у²
(3x+y)²=(3x+у)²