x⁴-x³ + abx- c²x + ab - c²=
=( x⁴-x³)+(abx+ab)- (c²x+c²)=
= x³(x-1)+ab(x+1) - c²(x+1)=
= x³(x-1) + (x+1)(ab- c²)
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Verified answer
x⁴-x³ + abx- c²x + ab - c²=
=( x⁴-x³)+(abx+ab)- (c²x+c²)=
= x³(x-1)+ab(x+1) - c²(x+1)=
= x³(x-1) + (x+1)(ab- c²)