[tex]\displaystyle (\frac{t}{b}-\frac{b}{t})*\frac{5tb}{t+b}=\frac{t^2-b^2}{bt}*\frac{5tb}{t+b}=(t-b)(t+b)*\frac{5}{t+b}=(t-b)*5=5(t-b)[/tex]
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[tex]\displaystyle (\frac{t}{b}-\frac{b}{t})*\frac{5tb}{t+b}=\frac{t^2-b^2}{bt}*\frac{5tb}{t+b}=(t-b)(t+b)*\frac{5}{t+b}=(t-b)*5=5(t-b)[/tex]