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elvira1234123
@elvira1234123
July 2022
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㏒7_(1-6*7^x)=2x+1 Нужно подробное решение
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MizoriesKun
㏒₇(1-6*7ˣ
)=2x+1
1-6*7ˣ= 7²ˣ⁺¹
1-6*7ˣ= 7*7²ˣ
7*7²ˣ+6*7ˣ-1=0 замена 7ˣ=а
7а²+6а-1=0
D=36+28=64 √64=8
a₁=(-6+8)/14= 1/7 7ˣ=1/7 x₁=-1
a₂=(-6-8)/14= -1 7ˣ= -1 решения нет
Ответ : х= -1
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Answers & Comments
1-6*7ˣ= 7²ˣ⁺¹
1-6*7ˣ= 7*7²ˣ
7*7²ˣ+6*7ˣ-1=0 замена 7ˣ=а
7а²+6а-1=0
D=36+28=64 √64=8
a₁=(-6+8)/14= 1/7 7ˣ=1/7 x₁=-1
a₂=(-6-8)/14= -1 7ˣ= -1 решения нет
Ответ : х= -1