[tex]y = x + 1 \\ x \: \epsilon\:( - \propto; \: + \propto)[/tex]
[tex]y = \frac{x + 1}{x - 1} \\ x - 1\neq0 \\ x\neq1 \\ x \:\epsilon \: ( - \propto; \: 1)U(1; \: + \propto)[/tex]
[tex]y = \frac{x + 1}{ {x}^{2} - 1 } \\ {x}^{2} - 1 \neq0 \\ (x - 1)(x + 1)\neq0 \\ x\neq1 \\ x\neq - 1 \\ x \: \epsilon \: ( - \propto; \: - 1)U( - 1; \: 1)U(1; \: + \propto)[/tex]
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Answers & Comments
а)
[tex]y = x + 1 \\ x \: \epsilon\:( - \propto; \: + \propto)[/tex]
б)
[tex]y = \frac{x + 1}{x - 1} \\ x - 1\neq0 \\ x\neq1 \\ x \:\epsilon \: ( - \propto; \: 1)U(1; \: + \propto)[/tex]
в)
[tex]y = \frac{x + 1}{ {x}^{2} - 1 } \\ {x}^{2} - 1 \neq0 \\ (x - 1)(x + 1)\neq0 \\ x\neq1 \\ x\neq - 1 \\ x \: \epsilon \: ( - \propto; \: - 1)U( - 1; \: 1)U(1; \: + \propto)[/tex]