Verified answer

Ответ:

Объяснение:

[tex]3(1-x)\geq 2(2x-2)\\3-3x\geq 4x-4\\-3x-4x\geq -4-3\\-7x\geq -7\\x\leq 1\\[/tex]

x∈ <-[tex]\infty}[/tex],1]   {x|x≤1}

[tex]y=\sqrt{4-2x} +\frac{1}{\sqrt{2} x} \\y=\sqrt{-2x+4} +\frac{1}{\sqrt{2} x} \\\sqrt{-2x+4}\\-2x+4\\\frac{1}{\sqrt{2} x}\\\sqrt{2x} \\2x\\[/tex]

x≤2

x∈R

x∈R \ {0}

x≥0

x∈R

x∈ <0,2]

[tex]y=\sqrt{x+5} +\frac{1}{\sqrt{2-x} } +\frac{1}{x^2-9} \\y=\sqrt{x+5} +\frac{1}{\sqrt{-x+2} } +\frac{1}{x^2-9} \\\sqrt{x+5} \\x+5\\\frac{1}{\sqrt{-x+2} }\\\sqrt{-x+2} \\-x+2\\\frac{1}{x^2-9}\\x^2-9\\[/tex]

x≥-5

x∈R

x∈R \ {2}

x≤2

x∈R

x∈R | {-3, 3}

x∈R

x∈ [-5, -3> ∪ <-3, 2>