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denisgotovtsev
@denisgotovtsev
July 2022
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75 БАЛЛОВ!
Найдите сумму значений параметра a , при которых сумма квадратов корней уравнения
x2 - 2ax + 2 * (a + 1) = 0
равна 20?
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IrkaShevko
Verified answer
D = 4a² - 8a - 8 ≥ 0
a² - 2a - 2 ≥ 0
D = 4 + 8 = 12
a1 = (2 - 2√3)/2 = 1 - √3
a1 = 1 + √3
т.е. а ∈ (-∞; 1 - √3) U (1 + √3; +∞)
по теореме Виета:
x1 + x2 = 2a
x1*x2 = 2a + 2
x1² + x2² = (x1 + x2)² - 2x1 * x2 = 4a² - 4a - 4 = 20
a² - a - 1 - 5 = 0
a² - a - 6 = 0
D = 1 + 24 = 25
a1 = (1-5)/2 = -2
a2 = (1+5)/2 = 3
сумма значений: -2 + 3 = 1
Ответ: 1
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Answers & Comments
Verified answer
D = 4a² - 8a - 8 ≥ 0a² - 2a - 2 ≥ 0
D = 4 + 8 = 12
a1 = (2 - 2√3)/2 = 1 - √3
a1 = 1 + √3
т.е. а ∈ (-∞; 1 - √3) U (1 + √3; +∞)
по теореме Виета:
x1 + x2 = 2a
x1*x2 = 2a + 2
x1² + x2² = (x1 + x2)² - 2x1 * x2 = 4a² - 4a - 4 = 20
a² - a - 1 - 5 = 0
a² - a - 6 = 0
D = 1 + 24 = 25
a1 = (1-5)/2 = -2
a2 = (1+5)/2 = 3
сумма значений: -2 + 3 = 1
Ответ: 1