Ответ:

[tex] log_{3}13.5 + log_{3}2 = log_{3}(13.5 \times 2) = \\ = log_{3}27 = log_{3} {3}^{3} = 3 log_{3}3 = 3[/tex]

.....

[tex] \frac{ log_{6}125}{log_{6} 25} = \frac{ log_{6} {5}^{3} }{ log_{6} {5}^{2} } = \frac{3 log_{6}5}{2 log_{6}5 } = \frac{3}{2} = 1.5 \\ [/tex]