Ответ:
[tex]1)1 + 2p - \frac{11}{ {p}^{2} } [/tex]
[tex]2)t - \frac{5}{t - 1} [/tex]
Объяснение:
[tex]1) \frac{ {p}^{2} + 2 {p}^{3} - 11}{ {p}^{2} } = \frac{ {p}^{2} + 2 {p}^{3} }{ {p}^{2} } - \frac{11}{ {p}^{2} } = \frac{ {p}^{2} (1 + 2p)}{ {p}^{2} } - \frac{11}{ {p}^{2} } = 1 + 2p - \frac{11}{ {p}^{2} } [/tex]
[tex]2) \frac{ {t}^{2} - t - 5 }{t - 1} = \frac{ {t}^{2} - t }{t - 1} - \frac{5}{t - 1} = \frac{t(t -1)}{t - 1} - \frac{5}{t - 1} = t - \frac{5}{t - 1} [/tex]
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Answers & Comments
Ответ:
[tex]1)1 + 2p - \frac{11}{ {p}^{2} } [/tex]
[tex]2)t - \frac{5}{t - 1} [/tex]
Объяснение:
[tex]1) \frac{ {p}^{2} + 2 {p}^{3} - 11}{ {p}^{2} } = \frac{ {p}^{2} + 2 {p}^{3} }{ {p}^{2} } - \frac{11}{ {p}^{2} } = \frac{ {p}^{2} (1 + 2p)}{ {p}^{2} } - \frac{11}{ {p}^{2} } = 1 + 2p - \frac{11}{ {p}^{2} } [/tex]
[tex]2) \frac{ {t}^{2} - t - 5 }{t - 1} = \frac{ {t}^{2} - t }{t - 1} - \frac{5}{t - 1} = \frac{t(t -1)}{t - 1} - \frac{5}{t - 1} = t - \frac{5}{t - 1} [/tex]