Объяснение:
1.По теореме Виета:
x1+x2=-2
x1*x2=-24
x1=-6
x2=4
2.Дискриминант.
D=16-4*2*(-17)=152
x1=4+[tex]\sqrt{152}[/tex]/4=1+[tex]\sqrt{38}[/tex]/2
x2=4-[tex]\sqrt{152}[/tex]/4=-1+[tex]\sqrt{38}[/tex]/2
3.Дискриминант.
D=100-4*1*37=100-148=-48 - корней нет.
Ответ:
1) x² + 2x - 24 = 0
D = 2² - 4 × 1 × (-24) = 4 + 96 = 100
x =
[tex] \frac{ - 2± \sqrt{100} }{2 \times 1} = \frac{ - 2±10}{2} [/tex]
x¹ =
[tex] \frac{ - 2 + 10}{2} = \frac{8}{2} = 4[/tex]
x² =
[tex] \frac{ - 2 - 10}{2} = \frac{ - 12}{2} = - 6[/tex]
2) 2x² - 4x - 17 = 0
D = (-4)² - 4 × 2 × (-17) = 16 + 136 = 152
[tex] \frac{4 + \sqrt{152} }{2 \times 2} = \frac{4 + \sqrt{152} }{4} [/tex]
[tex] \frac{4 - \sqrt{152} }{2 \times 2} = \frac{4 - \sqrt{152} }{4} [/tex]
3) x² - 10x + 37 = 0
D = (-10)² - 4 × 1 × 37 = 100 - 148 = -48
Корней нет, т.к. D < 0
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Answers & Comments
Объяснение:
1.По теореме Виета:
x1+x2=-2
x1*x2=-24
x1=-6
x2=4
2.Дискриминант.
D=16-4*2*(-17)=152
x1=4+[tex]\sqrt{152}[/tex]/4=1+[tex]\sqrt{38}[/tex]/2
x2=4-[tex]\sqrt{152}[/tex]/4=-1+[tex]\sqrt{38}[/tex]/2
3.Дискриминант.
D=100-4*1*37=100-148=-48 - корней нет.
Ответ:
1) x² + 2x - 24 = 0
D = 2² - 4 × 1 × (-24) = 4 + 96 = 100
x =
[tex] \frac{ - 2± \sqrt{100} }{2 \times 1} = \frac{ - 2±10}{2} [/tex]
x¹ =
[tex] \frac{ - 2 + 10}{2} = \frac{8}{2} = 4[/tex]
x² =
[tex] \frac{ - 2 - 10}{2} = \frac{ - 12}{2} = - 6[/tex]
2) 2x² - 4x - 17 = 0
D = (-4)² - 4 × 2 × (-17) = 16 + 136 = 152
x¹ =
[tex] \frac{4 + \sqrt{152} }{2 \times 2} = \frac{4 + \sqrt{152} }{4} [/tex]
x² =
[tex] \frac{4 - \sqrt{152} }{2 \times 2} = \frac{4 - \sqrt{152} }{4} [/tex]
3) x² - 10x + 37 = 0
D = (-10)² - 4 × 1 × 37 = 100 - 148 = -48
Корней нет, т.к. D < 0