Verified answer

[tex] {125}^{ \frac{1}{3} } - {3}^{0} = ( {5}^{3} ) {}^{ \frac{1}{3} } - 1 = 5 - 1 = 4[/tex]

[tex] {81}^{ \frac{1}{4} } + ( \frac{1}{2} ) {}^{ - 1} = (3 {}^{4} ) {}^{ \frac{1}{4} } + 2 = 3 + 2 = 5[/tex]

[tex] \frac{1}{3} \times 27 {}^{ \frac{2}{3} } = \frac{1}{3} \times ( {3}^{3} ) \frac{2}{3} = \frac{1}{3} \times {3}^{2} = \frac{9}{3} = 3[/tex]

[tex]16 \times 64 {}^{ - \frac{1}{2} } = \frac{16}{ \sqrt{64} } = \frac{16}{ \sqrt{ {8}^{2} } } = \frac{16}{8} = 2[/tex]

Ответ:

[tex]1)125 {}^{ \frac{1}{3} } - 3 {}^{0} = (5 {}^{ 3 }) {}^{ \frac{1}{3} } - 1 = 5 - 1 = 4[/tex]

[tex]2)81 {}^{ \frac{1}{4} } + ( \frac{1}{2 {} } ) {}^{ - 1} =( 3 {}^{4} ) {}^{ \frac{1}{4} } + 2 = 3 + 2 = 5[/tex]

[tex]3)( \frac{1}{3 }) \times 27 {}^{ \frac{2}{3} } = 3 {}^{ - 1} \times (3 {}^{3} ) {}^{ \frac{2}{3} } = 3 {}^{ - 1} \times 3 {}^{2} = 3 {}^{2 - 1} = 3[/tex]

Объяснение:

[tex]4)16 \times 64 {}^{ - \frac{1}{2} } = 2 {}^{4} \times (2 {}^{6} ) {}^{ - \frac{1}{2} } = 2 {}^{4} \times 2 {}^{-3} = 2 {}^{4 - 3} = 2 {}^{1} = 2[/tex]