Ответ:
по теореме Виета
a = 1; p = 14 ; p = 40
x1+x2 = - p = - 14
x1×x2 = q = 40
-10-4 = - 14
-10×(-4)= 40
x1 = -10
x2 = -4
x²-14x-40=1(x+10)(x+4)
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Ответ:
по теореме Виета
a = 1; p = 14 ; p = 40
x1+x2 = - p = - 14
x1×x2 = q = 40
-10-4 = - 14
-10×(-4)= 40
x1 = -10
x2 = -4
x²-14x-40=1(x+10)(x+4)