Ответ: m(CuSO₄) = 80г Объяснение:H₂SO₄ + CuO = CuSO₄ + H₂Om(H₂SO₄) = 49гM(H₂SO₄) = 2 + 32 + 16 × 4 = 98 г\мольn(H₂SO₄) = = = 0.5 мольn(H₂SO₄) = n(CuS.
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Ответ: m(CuSO₄) = 80г Объяснение:H₂SO₄ + CuO = CuSO₄ + H₂Om(H₂SO₄) = 49гM(H₂SO₄) = 2 + 32 + 16 × 4 = 98 г\мольn(H₂SO₄) = = = 0.5 мольn(H₂SO₄) = n(CuS.