Verified answer

Ответ:

Сложим дроби с одинаковыми знаменателями .

[tex]\displaystyle \frac{k^2-6}{k+2}-\frac{3k-10}{k+2}+\frac{5k-k^2}{k+2}=\frac{k^2-6-3k+10+5k-k^2}{k+2}=\\\\\\=\frac{(k^2-k^2)+(-8+10)+(-3k+5k)}{k+2}=\boldsymbol{\frac{2k+2}{k+2}\ \ ,\ \ \ \ k\ne -2}[/tex]