Ответ:
Пошаговое объяснение:
[tex]3) 2x^{2} + 7x + 6 = 0\\D = 7^{2} -4*2*6=1\\x_{1} =\frac{-7 + 1}{4} = -\frac{3}{2} \\x_{2} =\frac{-7 - 1}{4} = -2[/tex]
[tex]1)-37x+27=0\\-37x=-27\\x=\frac{27}{37}[/tex]
[tex]2)x^{2} -2x-9=0\\D=(-2)^{2} -4*1*(-9)=40, \sqrt{D} = 2\sqrt{10}\\ x_{1} = \frac{2+2\sqrt{10}}{2} =1+\sqrt{10} \\ x_{2} = \frac{2-2\sqrt{10}}{2} =1-\sqrt{10}[/tex]
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Ответ:
Пошаговое объяснение:
[tex]3) 2x^{2} + 7x + 6 = 0\\D = 7^{2} -4*2*6=1\\x_{1} =\frac{-7 + 1}{4} = -\frac{3}{2} \\x_{2} =\frac{-7 - 1}{4} = -2[/tex]
[tex]1)-37x+27=0\\-37x=-27\\x=\frac{27}{37}[/tex]
[tex]2)x^{2} -2x-9=0\\D=(-2)^{2} -4*1*(-9)=40, \sqrt{D} = 2\sqrt{10}\\ x_{1} = \frac{2+2\sqrt{10}}{2} =1+\sqrt{10} \\ x_{2} = \frac{2-2\sqrt{10}}{2} =1-\sqrt{10}[/tex]