Ответ:
[tex]0[/tex]
Объяснение:
[tex]sin120^0+cos120^0*tg60^0=sin(90^0+30^0)+cos(90^0+30^0)*tg60^0=\\\\=cos30^0-sin30^0*tg60^0=\frac{\sqrt{3}}{2}-\frac{1}{2}*\sqrt{3}=\frac{\sqrt{3}}{2}- \frac{\sqrt{3}}{2}=0[/tex]
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Answers & Comments
Ответ:
[tex]0[/tex]
Объяснение:
[tex]sin120^0+cos120^0*tg60^0=sin(90^0+30^0)+cos(90^0+30^0)*tg60^0=\\\\=cos30^0-sin30^0*tg60^0=\frac{\sqrt{3}}{2}-\frac{1}{2}*\sqrt{3}=\frac{\sqrt{3}}{2}- \frac{\sqrt{3}}{2}=0[/tex]