Ответ:

[tex]x = 0\\y = \frac{1}{3}[/tex]

Объяснение:

[tex]\left \{ {{\frac{3y - 2x}{3} + \frac{4x - y}{2} = \frac{x + 1}{6} } \atop {\frac{5x + y}{5} - \frac{y - 2x}{3} = -\frac{2}{45} }} \right.\\\left \{ {{2(3y - 2x) + 3(4x - y) = x + 1} \atop {9(5x + y) - 15(y - 2x) = -2}} \right.\\\left \{ {{6y - 4x + 12x - 3y - x = 1} \atop {45x + 9y - 15y + 30x = -2}} \right.\\\left \{ {{8x + 3y = 1} \atop {75x - 6y = -2}} \right.\\\left \{ {{16x + 6y = 2} \atop {75x - 6y = -2}} \right.\\91x = 0\\x = 0\\3y = 1 - 8 * 0 = 1\\y = \frac{1}{3}[/tex]