[tex]S=\int\limits^1_{-1} ({1-x^2} )\, dx=(x-\frac{x^3}{3})|1_{-1}=(1-\frac{1^3}{3})-((-1)-\frac{(-1)^3}{3})=\frac{4}{3}[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]S=\int\limits^1_{-1} ({1-x^2} )\, dx=(x-\frac{x^3}{3})|1_{-1}=(1-\frac{1^3}{3})-((-1)-\frac{(-1)^3}{3})=\frac{4}{3}[/tex]