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маша23467
@маша23467
July 2022
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найдите сумму бесконечной убывающей геометрической прогрессии 2/3, 1/2, 3/8,...
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sedinalana
B1=2/3 b2=1/2
q=b2/b1
q=1/2:2/3=1/2*3/2=3/4
S=b1/(1-q)
S=2/3:(1-3/4)=2/3:1/4=2/3*4=8/3=2 2/3
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Answers & Comments
q=b2/b1
q=1/2:2/3=1/2*3/2=3/4
S=b1/(1-q)
S=2/3:(1-3/4)=2/3:1/4=2/3*4=8/3=2 2/3