Ответ:

6(k-t)²

--------=-2(k-t)

-3(k-t)

Verified answer

Объяснение:

[tex]\displaystyle\\4)\ \frac{m^6-m^4}{m^3+m^2} =\frac{m^4(m^2-1)}{m^2(m+1)}=\frac{m^2(m+1)(m-1)}{m+1} =m^2(m-1)=m^3-m^2.[/tex]

[tex]\displaystyle\\6)\ \frac{6(k-t)^2}{3t-3k}=\frac{6(t-k)^2}{3(t-k)} =2(t-k)=2t-2k.[/tex]

[tex]8)\ \frac{(p-q)^2}{(q-p)^2} =\frac{(p-q)^2}{(p-q)^2} =1.[/tex]