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GURU921
@GURU921
July 2022
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(8x+3)^2+(6x+4)^2+4x
Представьте выражение в виде квадрата двучлена
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Gerren
(8x+3)^2+(6x+4)^2+4x=64x^2+48x+9+36x^2+48x+16+4x=100x^2+100x+25=(10x+5)^2
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