Відповідь: фото
Покрокове пояснення:
Ответ:
Пошаговое объяснение:
[tex]9^{\frac{1}{2}} = \sqrt[]{9} = 3[/tex]
[tex]36^{-\frac{1}{2}} = \sqrt[]{36^{-1}} = \sqrt[]{{\frac{1}{36}}} = {\frac{1}{6}}[/tex]
[tex]0.125^{-\frac{1}{3}} = \sqrt[3]{0.125^{-1}} = \sqrt[3]{({\frac{1}{8}})^{-1}} = \sqrt[3]{8} = 2[/tex]
[tex]0.00032^{0.4} = 0.00032^{\frac{2}{5}} = (0.2^5)^\frac{2}{5} =0.2^2 = 0.04[/tex]
[tex](3\frac{3}{8})^{-\frac{2}{3}} = (\frac{27}{8})^{-\frac{2}{3}} = ((\frac{3}{2})^3)^{-\frac{2}{3}} = (\frac{3}{2})^{-2} = (\frac{2}{3})^{2} =\frac{4}{9}[/tex]
[tex](2\frac{10}{27})^{-\frac{1}{6}} = (\frac{64}{27})^{-\frac{1}{6}} = ((\frac{4}{3})^3)^{-\frac{1}{6}} = (\frac{4}{3})^{-\frac{1}{2}} = (\frac{3}{4})^{\frac{1}{2}} =\sqrt{\frac{3}{4}} =\frac{\sqrt{3}}{2}[/tex]
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Answers & Comments
Відповідь: фото
Покрокове пояснення:
Ответ:
Пошаговое объяснение:
[tex]9^{\frac{1}{2}} = \sqrt[]{9} = 3[/tex]
[tex]36^{-\frac{1}{2}} = \sqrt[]{36^{-1}} = \sqrt[]{{\frac{1}{36}}} = {\frac{1}{6}}[/tex]
[tex]0.125^{-\frac{1}{3}} = \sqrt[3]{0.125^{-1}} = \sqrt[3]{({\frac{1}{8}})^{-1}} = \sqrt[3]{8} = 2[/tex]
[tex]0.00032^{0.4} = 0.00032^{\frac{2}{5}} = (0.2^5)^\frac{2}{5} =0.2^2 = 0.04[/tex]
[tex](3\frac{3}{8})^{-\frac{2}{3}} = (\frac{27}{8})^{-\frac{2}{3}} = ((\frac{3}{2})^3)^{-\frac{2}{3}} = (\frac{3}{2})^{-2} = (\frac{2}{3})^{2} =\frac{4}{9}[/tex]
[tex](2\frac{10}{27})^{-\frac{1}{6}} = (\frac{64}{27})^{-\frac{1}{6}} = ((\frac{4}{3})^3)^{-\frac{1}{6}} = (\frac{4}{3})^{-\frac{1}{2}} = (\frac{3}{4})^{\frac{1}{2}} =\sqrt{\frac{3}{4}} =\frac{\sqrt{3}}{2}[/tex]