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Barby1978
@Barby1978
July 2022
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Помогите решить с подробным решением пожалуйста. Заранее спасибо!!!
1) 6^12/(3^11*4^5)
2) 33^3/(9*11^2)
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mmb1
Verified answer
1) 6^12/(3^11*4^5)
6^12/(3^11*4^5)=2^12*3^12/(3^11*2^5^*2^5)=2^12*3^12/(3^11*2^10)=3^(12-11)*2^(12-10)=3*4=12
2) 33^3/(9*11^2)
33^3/(9*11^2)=11^3*3^3/(3^2*11^2)=11^(3-2)*3^(3-2)=33
1 votes
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KsuDirnt
Вот тебе мое решение, думаю, поможет :)
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Answers & Comments
Verified answer
1) 6^12/(3^11*4^5)6^12/(3^11*4^5)=2^12*3^12/(3^11*2^5^*2^5)=2^12*3^12/(3^11*2^10)=3^(12-11)*2^(12-10)=3*4=12
2) 33^3/(9*11^2)
33^3/(9*11^2)=11^3*3^3/(3^2*11^2)=11^(3-2)*3^(3-2)=33