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molenecs
@molenecs
August 2022
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tdutif2014
2) 2sinx-1=0
2sinx=-1
sinx=-1/2
x=(-1)n+1*П/6 + Пn
5) sin2x-2sinx=0
2sinx*cosx-2sinx=0
2sinx(cosx-1)=0
sinx=0
x=Пи*n, n ∈ Z cosx-1=0
cosx=1
x=2Пи*n, n ∈ Z
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Answers & Comments
2sinx=-1
sinx=-1/2
x=(-1)n+1*П/6 + Пn
5) sin2x-2sinx=0
2sinx*cosx-2sinx=0
2sinx(cosx-1)=0
sinx=0
x=Пи*n, n ∈ Z cosx-1=0
cosx=1
x=2Пи*n, n ∈ Z