как решить дробь (3 1/4+2 1/6):2 3/5-2/3-2/3*4/9. Created by 555kirill555k. matematika-ru

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нбмелу5ена65акалв (3 1/4+2 1/6):2 3/5-2/3-2/3*4/9=1 13/108

1) 13/4+13/6=3*13/12+2*13/12= 39/12+26/12=65/12
2)65/12:2 3/5=65/12:13/5=65/12*5/13=5/12*5/1=25/12
3) 2/3*4/9=8/27
4) 25/12-2/3=25/12-4*2/12=25/12-8/12=17/12
5) 17/12-8/27=9*17/108-4*8/108=153/108-32/108=121/108= 1 13/108

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наст55 (3*1/2+2*1/6):2
3/4+1/3)*1/2
(3/4+1/3)*1/2
9+4/12*1/2
13/12*1/2
13/24

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