Ответ: 3

[tex] \frac{ {3}^{ - 4} \times {9}^{ - 8} }{ {27}^{ - 7} } = \frac{ {3}^{ - 4} \times { ({3}^{2}) }^{ - 8} }{ {( {3}^{3}) }^{ - 7} } = \frac{ {3}^{ - 4} \times {3}^{ - 16} }{ {3}^{ - 21} } = \frac{ {3}^{ - 20} }{ {3}^{ - 21} } = \frac{1}{ {3}^{ - 1} } = 3[/tex]