Ответ:
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[tex]\displaystyle 1)\sqrt{125*26*52}=\sqrt{169000}=130\sqrt{10}\\ \\2)\frac{5m-9}{m-2}-\frac{3-2m}{2-m}=\frac{5m-9}{m-2}-\frac{3-2m}{-(m-2)}=\frac{5m-9}{m-2}+\frac{3-2m}{m-2}=\frac{5m-9+3-2m}{m-2}=\\\frac{3m-6}{m-2}=\frac{3(m-2)}{m-2}=3\\ \\[/tex]
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Ответ:
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[tex]\displaystyle 1)\sqrt{125*26*52}=\sqrt{169000}=130\sqrt{10}\\ \\2)\frac{5m-9}{m-2}-\frac{3-2m}{2-m}=\frac{5m-9}{m-2}-\frac{3-2m}{-(m-2)}=\frac{5m-9}{m-2}+\frac{3-2m}{m-2}=\frac{5m-9+3-2m}{m-2}=\\\frac{3m-6}{m-2}=\frac{3(m-2)}{m-2}=3\\ \\[/tex]