Найдите сумму первых: 6 членов геометрической прогрессии 32/27; 16/9;...
b1=32/27
q=16/9 : 32/27 = 3/2
S₆=
S₆==665/27=24 17/27
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
b1=32/27
q=16/9 : 32/27 = 3/2
S₆=
S₆==665/27=24 17/27