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hootrel
@hootrel
March 2022
2
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Освободиться от иррациональности в знаменателе дроби
1/√а-√b
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MizoriesKun
Vashe zadanie resheno
1 votes
Thanks 0
Kixcertborn2
Verified answer
1 1*(√a +√b) √a +√b √a +√b
------------ = ------------------------- = ----------------- = ---------------------
√a -√b (√a -√b)(√a +√b) √a² -√b² a - b
0 votes
Thanks 1
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Verified answer
1 1*(√a +√b) √a +√b √a +√b------------ = ------------------------- = ----------------- = ---------------------
√a -√b (√a -√b)(√a +√b) √a² -√b² a - b