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Me163
@Me163
July 2022
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a-n\m - a = 2y - m\m. y - ? a- ?
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MizoriesKun
(a-n)/(m-a)=(2y-m)/m
(a-n)*m=(2y-m)*(m-a)
ma-mn=2my-m²-2ya+ma
ma-mn-ma=2my-m²-2ya
m²-mn-2my=-2ya
a=(m²-mn-2my) / (-2y) = - m(m-n-2y) /2y
m²-mn-2my=-2ya
m²-mn=2my-2ya
m²-mn=2y*(m-a)
y=(m²-mn) /2(m-a) = m(m-n)/2(m-a)
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Me163
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Answers & Comments
(a-n)*m=(2y-m)*(m-a)
ma-mn=2my-m²-2ya+ma
ma-mn-ma=2my-m²-2ya
m²-mn-2my=-2ya
a=(m²-mn-2my) / (-2y) = - m(m-n-2y) /2y
m²-mn-2my=-2ya
m²-mn=2my-2ya
m²-mn=2y*(m-a)
y=(m²-mn) /2(m-a) = m(m-n)/2(m-a)