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Me163
@Me163
August 2021
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выписаны первые несколько членов геометрической прогрессии 7, -35, 175... найдите сумму первых 4 ее членов
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sedinalana
Verified answer
B1=7
b2=-35
q=b2/b1=-35/7=-5
S4=b1*(1-q^4)/(1-q)
S4=7*(1-625)/(1+5)=7*(-624)/6=7*(-104)=-728
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Answers & Comments
Verified answer
B1=7b2=-35
q=b2/b1=-35/7=-5
S4=b1*(1-q^4)/(1-q)
S4=7*(1-625)/(1+5)=7*(-624)/6=7*(-104)=-728