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sashunya2003minayev
@sashunya2003minayev
August 2022
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Числа а1 а2 а3... аn an+1 образуют арифметическую прогрессию доказать что
1/a1*a2+1/a2*a3+...+1/an*an+1 = n/a1 * an+1
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igorShap
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