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sechevayana959
@sechevayana959
August 2022
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ABCD-ромб,AC пересекает BD=O,AO=7,BO=8.Найдите площадь ABCD.
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triplermpage
S ромба = 1
/2 (ac*bd) , тоесть
S=1/2(2AO*2BO)=56
1 votes
Thanks 4
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Answers & Comments
S=1/2(2AO*2BO)=56