Home
О нас
Products
Services
Регистрация
Войти
Поиск
inkognitous
@inkognitous
August 2022
1
15
Report
Алгебра ( 2 задания = 50 баллов)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
oganesbagoyan
Verified answer
F(x) =(x²+3x)/(x+4) . || = x -x/(x+4) . ||
f'(x) = ( (x²+3x)/(x+4) ) ' =
(
(x²+3x)'(x+4) -(x²+3x)*(x+4)'
) /(
x+4)² =
= ((2x+3)(x+4) -(x² +3x)) /
(
x+4)² =(x²+8x+12)/(x+4) =(x+2)(x+6)/(x+4)² .
* * * f(x) =(x²+3x)/(x+4) = x -x/(x+4) . * * *
f '(x) =( x -x/(x+4) )' =1 -(1*(x+4) -1*x)/(x+4)² = 1 -4/(x+4)² =((x+4)² -4)/(x+4)² =
(x+4-2)*(x+4+2)/(x+4)² =(x+2)(x+6)/(x+4)² .
f'(x) =0 ⇔(x+2)(x+6)=0 ⇒
x=2, x=4
.
------------
f(x) = -x³ -3x² +9x + 3 .
f '(x) =( -x³ -3x² +9x + 3)' = -3x² -6x +9 = -3(x² +2x -3) = -2(x+3)(x-1).
Функция возрастает(↑) , если f '(x)≥0 .
-2(x+3)(x-1)≥0⇔ (x+3)(x-1)≤0⇒
x∈[ -3;1].
2 votes
Thanks 1
More Questions From This User
See All
inkognitous
July 2023 | 0 Ответы
50 64a913d71a658
Answer
inkognitous
July 2023 | 0 Ответы
b97b8906d6ba4744cc9917e4fd28f547
Answer
inkognitous
July 2023 | 0 Ответы
50 64a885059c6d6
Answer
inkognitous
July 2023 | 0 Ответы
50 64a8557ef31f5
Answer
inkognitous
July 2023 | 0 Ответы
50 64a7d89e271be
Answer
inkognitous
July 2023 | 0 Ответы
1 80 64a795eb2442a
Answer
inkognitous
July 2023 | 0 Ответы
fx 2 3 2 1
Answer
inkognitous
July 2023 | 0 Ответы
538e0c4c6457018ed8c432a780d23623
Answer
inkognitous
July 2023 | 0 Ответы
100 64a6e3458d79a
Answer
inkognitous
July 2023 | 0 Ответы
cos125cos55
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Алгебра ( 2 задания = 50 баллов)..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
F(x) =(x²+3x)/(x+4) . || = x -x/(x+4) . ||f'(x) = ( (x²+3x)/(x+4) ) ' =((x²+3x)'(x+4) -(x²+3x)*(x+4)' ) /(x+4)² =
= ((2x+3)(x+4) -(x² +3x)) / (x+4)² =(x²+8x+12)/(x+4) =(x+2)(x+6)/(x+4)² .
* * * f(x) =(x²+3x)/(x+4) = x -x/(x+4) . * * *
f '(x) =( x -x/(x+4) )' =1 -(1*(x+4) -1*x)/(x+4)² = 1 -4/(x+4)² =((x+4)² -4)/(x+4)² =
(x+4-2)*(x+4+2)/(x+4)² =(x+2)(x+6)/(x+4)² .
f'(x) =0 ⇔(x+2)(x+6)=0 ⇒ x=2, x=4.
------------
f(x) = -x³ -3x² +9x + 3 .
f '(x) =( -x³ -3x² +9x + 3)' = -3x² -6x +9 = -3(x² +2x -3) = -2(x+3)(x-1).
Функция возрастает(↑) , если f '(x)≥0 .
-2(x+3)(x-1)≥0⇔ (x+3)(x-1)≤0⇒ x∈[ -3;1].