sangers1959

Verified answer

√((3,02-2,98)/√(40²-32²))=
=√((3,02+2,98)(3,02-2,98)/√(40+32)(40-32))=
=√((6*0,04/√(72*8))=√(6*0,04/24)=√0,01=0,1.
√(66√(50²-40²)/√(44²+33²))=√(66√((50+40)(50-40))/√3025)=
=√(66√900/55)=√(66*30/55)=√(180/5)=√36=6.