[tex]\displaystyle\bf\\a_{1} =-7\\\\d=2\\\\a_{5} =a_{1} +4d=-7+4\cdot2=-7+8=1\\\\\boxed{\boxed{a_{5} =1}}\\\\a_{22} =a_{1} +21d=-7+21\cdot 2=-7+42=35\\\\\\S_{22} =\frac{a_{1} +a_{22} }{2} \cdot 22=(a_{1}+a_{22} )\cdot 11=(-7+35)\cdot 11=28\cdot 11=308\\\\\\\boxed{\boxed{S_{22} =308}}[/tex]
Ответ:
а5=1 S22=308
Объяснение:
решение внизу
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[tex]\displaystyle\bf\\a_{1} =-7\\\\d=2\\\\a_{5} =a_{1} +4d=-7+4\cdot2=-7+8=1\\\\\boxed{\boxed{a_{5} =1}}\\\\a_{22} =a_{1} +21d=-7+21\cdot 2=-7+42=35\\\\\\S_{22} =\frac{a_{1} +a_{22} }{2} \cdot 22=(a_{1}+a_{22} )\cdot 11=(-7+35)\cdot 11=28\cdot 11=308\\\\\\\boxed{\boxed{S_{22} =308}}[/tex]
Ответ:
а5=1 S22=308
Объяснение:
решение внизу