Ответ:
А) b^2 - b - 11
Б) 2x^2 - 4x + 19
Объяснение:
А) (b-3)(b+3)-(b+2) = b^2 - 9 - (b+2) = b^2 - b - 11
Б) (x-1)(x+1)+(x+1)(x-5)-(x-5)(x+5) = (x^2 - 1) + (x^2 - 4x - 5) - (x^2 - 25) = x^2 + x^2 - x^2 - 4x - 1 - 5 + 25 = 2x^2 - 4x + 19
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Verified answer
Ответ:
А) b^2 - b - 11
Б) 2x^2 - 4x + 19
Объяснение:
А) (b-3)(b+3)-(b+2) = b^2 - 9 - (b+2) = b^2 - b - 11
Б) (x-1)(x+1)+(x+1)(x-5)-(x-5)(x+5) = (x^2 - 1) + (x^2 - 4x - 5) - (x^2 - 25) = x^2 + x^2 - x^2 - 4x - 1 - 5 + 25 = 2x^2 - 4x + 19