[tex]\displaystyle\bf\\x^{2} -bx+6=0\\\\x=2\\\\2^{2} -b\cdot 2+6=0\\\\4-2b+6=0\\\\10-2b=0\\\\2b=10\\\\\boxed{b=5}[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\displaystyle\bf\\x^{2} -bx+6=0\\\\x=2\\\\2^{2} -b\cdot 2+6=0\\\\4-2b+6=0\\\\10-2b=0\\\\2b=10\\\\\boxed{b=5}[/tex]