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Ксюша2507
@Ксюша2507
August 2022
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В геометрической прогрессии сумма первых пяти членов равна -242, b4/b1 = 27, bn = -486. Чему равно n?
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ShirokovP
Verified answer
S5 = - 242
b4/b1 = 27 ==> q^3 = 27 ==> q= 3
b1*(1 - 3^5)/(1 - 3) = - 242
b1*(1 - 243)/(-2) = - 242
b1 = - 2
bn = b1*q^(n - 1) = - 486
- 2*3^(n - 1) = - 486
2*3^n*1/3 = 486
3^n = 729
3^n = 3^6
n = 6
1 votes
Thanks 1
Ксюша2507
Ответ должен получится 6
ShirokovP
обнови!
Ксюша2507
Спасибо большое!
ShirokovP
Не за что
amin07am
Verified answer
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2 votes
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Answers & Comments
Verified answer
S5 = - 242b4/b1 = 27 ==> q^3 = 27 ==> q= 3
b1*(1 - 3^5)/(1 - 3) = - 242
b1*(1 - 243)/(-2) = - 242
b1 = - 2
bn = b1*q^(n - 1) = - 486
- 2*3^(n - 1) = - 486
2*3^n*1/3 = 486
3^n = 729
3^n = 3^6
n = 6
Verified answer
Ответ ответ ответ ответ ответ