b^3 по основанию 6...

June 2022 1 8 Report

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(216*корень 5 степени из а^2)/ b^3 по основанию 6

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NNNLLL54

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$log_{\sqrt6}\frac{216\cdot \sqrt[5]{a^2}}{b^3}=2\cdot log_6\frac{6^3\cdot a^{\frac{2}{5}}}{b^3}=2\cdot (log_6(6^3\cdot a^{\frac{2}{5}})-log_6b^3)=\\\\=2\cdot (3log_66+\frac{2}{5}log_6a-3log_6b)=6+\frac{4}{5}log_6a-6log_6b$

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