Ответ:

[tex]\frac{8}{5a^{\frac{1}{4}}}[/tex]

Объяснение:

[tex]\frac{a^{\frac{1}{4}}-2,4}{a^{\frac{1}{2}}-2a^{\frac{1}{4}}}-\frac{a^{\frac{1}{4}}-3}{5a^{\frac{1}{4}}-10}+\frac{a^{\frac{1}{4}}+2}{5a^{\frac{1}{4}}}[/tex]

ми підставляємо

[tex]a^{\frac{1}{4}}=x\\\\a^{\frac{1}{2}}=x^2[/tex]

[tex]\frac{x-2,4}{x^2-2x}-\frac{x-3}{5x-10}+\frac{x+2}{5x}=[/tex]

[tex]\frac{x-2,4}{x(x-2)}-\frac{x-3}{5(x-2)}+\frac{x+2}{5x}=[/tex]

[tex]\frac{5(x-2,4)}{5x(x-2)}-\frac{x(x-3)}{5x(x-2)}+\frac{(x+2)(x-2)}{5x(x-2)}=[/tex]

[tex]\frac{5(x-2,4)-x(x-3)+(x+2)(x-2)}{5x(x-2)}=[/tex]

[tex]\frac{5x-12-x^2+3x+x^2-4}{5x(x-2)}=[/tex]

[tex]\frac{8x-16}{5x(x-2)}=\frac{8(x-2)}{5x(x-2)}=\frac{8}{5x}[/tex]

[tex]\frac{8}{5a^{\frac{1}{4}}}[/tex]