Verified answer

Объяснение:

1) RQ=√(PQ²+PR²)=√(8²+5²)=√(64+25)=√89≈9,4334

sinQ=PR/RQ=5/9,4334≈0,53

cosQ=PQ/RQ=8/9,4334≈0,848

tgQ=PR/PQ=5/8=0,625

2) FH=√(FG²+GH²)=√(7²+5²)=√(49+25)=√74≈8,6

cosF=FG/FH=7/8,6≈0,814

sinF=GH/FH=5/8,6≈0,5813

tgF=GH/FG=5/7

3) SR=9

cosS=SM/9

sinS=MR/9

tgS=MR/SM