Доказать: ((4sina*cosa*cos2a)/(cos^2 2a-sin^2 2a))*ctg4a=1 Спасибо!
=((2sin2a*cos2a)/(cos 4a))*ctg4a=(sin4a/cos4a)*ctg4a=tg4a*ctg4a=1
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=((2sin2a*cos2a)/(cos 4a))*ctg4a=(sin4a/cos4a)*ctg4a=tg4a*ctg4a=1