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arishka122
@arishka122
August 2022
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1/cos^2a-cos^2a-tg^2a
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qwe777
Cos²a-ctg²a=cos²a- cos²a/sin²a=1/sin²a*(cos²a*sin²a-cos²a)=1/sin²a*cos²a*(sin²a-1)=
=1/sin²a * cos²a *(-cos²a)=-cos⁴a *1/sin²a
2 votes
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