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arishka122
@arishka122
July 2022
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найти первый член и разность арифметической прогрессии если a1+a5=7,a15=32
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NadDer
Решим систему:
a1+(a1+4d) = 7
a1+14d = 32
2a1+4d = 7
a1+14d = 32 (*на -2)
2a1+4d = 7
-2a1-28d = -64
Складываем
-24d = -57
d =2,375
2a1+4*2,375 = 7
2a1+9,5 = 7
2a1 = -2,5
a1 = 1,25
2 votes
Thanks 6
arishka122
Спасибо, выручили
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Answers & Comments
a1+(a1+4d) = 7
a1+14d = 32
2a1+4d = 7
a1+14d = 32 (*на -2)
2a1+4d = 7
-2a1-28d = -64
Складываем
-24d = -57
d =2,375
2a1+4*2,375 = 7
2a1+9,5 = 7
2a1 = -2,5
a1 = 1,25