Объяснение:
..........................
Ответ:
cos(2)-cos(x)=cos(3x)
-2sin(2x+x/2)sin(2-x/2)
-2sin(3x/2)sin(2x-x/
-2sin (3x/2)sin(x/2)=cos(3x)
-2sin(3x/2)sin(x/2)-cos(3x)=cos(3x)-cos(3xx)
-2sin(3x/2)sin(x/2)-cos(3x)=
x=π/4+kπ/2,k є Z.
x=π/3+2kπ,k є Z.
x=5π/3+2kπ,k є Z.
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Answers & Comments
Объяснение:
..........................
Ответ:
cos(2)-cos(x)=cos(3x)
-2sin(2x+x/2)sin(2-x/2)
-2sin(3x/2)sin(2x-x/
-2sin (3x/2)sin(x/2)=cos(3x)
-2sin(3x/2)sin(x/2)-cos(3x)=cos(3x)-cos(3xx)
-2sin(3x/2)sin(x/2)-cos(3x)=
x=π/4+kπ/2,k є Z.
x=π/3+2kπ,k є Z.
x=5π/3+2kπ,k є Z.
Объяснение: