cos^2x-sin^2x-2√3sinxcosx=1. Помогите решить)))пожалуйста. Created by Sladkoeschka1998. matematika-ru

cos^2x-sin^2x-2√3sinxcosx=1. Помогите решить)))пожалуйста...

Sladkoeschka1998 @Sladkoeschka1998

August 2022 1 3 Report

cos^2x-sin^2x-2√3sinxcosx=1. Помогите решить)))пожалуйста

Answers & Comments

treezor Cos^2x-sin^2x-2√3sinxcosx=sin^2x+cos^2x
-2sin^2x-2√3sinxcosx=0 | : на 2sin^2x
-1-√3ctgx=0
-√3ctgx=1
√3ctgx=-1
ctgx=-1/√3
ctgx=-√3/3
x=-Π/3+Πn, n€Z

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