1-cos2x-sinx/cosx-sin2x
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Использованы формулы
cos (2α) = 1 - 2 sin²α
sin (2α) = 2 sin α · cos α
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Verified answer
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Использованы формулы
cos (2α) = 1 - 2 sin²α
sin (2α) = 2 sin α · cos α